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35x+6x^2=-25
We move all terms to the left:
35x+6x^2-(-25)=0
We add all the numbers together, and all the variables
6x^2+35x+25=0
a = 6; b = 35; c = +25;
Δ = b2-4ac
Δ = 352-4·6·25
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-25}{2*6}=\frac{-60}{12} =-5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+25}{2*6}=\frac{-10}{12} =-5/6 $
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